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x^2+11.24x-237.055=0
a = 1; b = 11.24; c = -237.055;
Δ = b2-4ac
Δ = 11.242-4·1·(-237.055)
Δ = 1074.5576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11.24)-\sqrt{1074.5576}}{2*1}=\frac{-11.24-\sqrt{1074.5576}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11.24)+\sqrt{1074.5576}}{2*1}=\frac{-11.24+\sqrt{1074.5576}}{2} $
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